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軟件設(shè)計(jì)師每日一練試題內(nèi)容(2024/4/19)
試題1
下圖屬于 UML 中的(1),其中,AccountManagement 需要(2)。
(1)A、組件圖
B、部署圖
C、類圖
D、對(duì)象圖
(2)A、實(shí)現(xiàn) IdentityVerifier 接口并被 CreditCardServices 調(diào)用
B、調(diào)用 CreditCardServices 實(shí)現(xiàn)的 IdentityVerifier 接口
C、實(shí)現(xiàn) IdentityVerifier 接口并被 Logger 調(diào)用
D、調(diào)用 Logger 實(shí)現(xiàn)的 IdentityVerifier 接口
查看答案
試題參考答案:A、B
試題解析與討論:www.ichunya.com/exam/ExamDay.aspx?t1=4&day=2024/4/19
試題2
美國(guó)卡內(nèi)基—梅隆大學(xué)SEI提出的CMM模型將軟件過程的成熟度分為5個(gè)等級(jí),以下選項(xiàng)中,屬于可管理級(jí)的特征是( )。
A、工作無(wú)序,項(xiàng)目進(jìn)行過程中經(jīng)常放棄當(dāng)初的計(jì)劃
B、建立了項(xiàng)目級(jí)的管理制度
C、建立了企業(yè)級(jí)的管理制度
D、軟件過程中活動(dòng)的生產(chǎn)率和質(zhì)量是可度量的
查看答案
試題參考答案:D
試題解析與討論:www.ichunya.com/exam/ExamDay.aspx?t1=4&day=2024/4/19
試題3
在Python3中,表達(dá)式list(range(11)【10∶0∶-2】的值為()查看答案
試題參考答案:B
試題解析與討論:www.ichunya.com/exam/ExamDay.aspx?t1=4&day=2024/4/19
試題4
Software entities are more complex for their size than perhaps any other humanconstruct, because no two parts are alike (at least above the statement level). If they are, wemake the two similar parts into one, a( 71 ), open or closeD. In this respect software systemsdiffer profoundly from computers, buildings, or automobiles, where repeated elements abound.
Digital computers . are themselves more complex than most things people build;they have very large numbers of states This makes conceiving, describing, and testing them harD. Software systems have orders of magnitude more( 72 )than computers do
Likewise, a scaling-up of a software entity is not m erely a repetition of the same elementsm larger size; it is necessarily an mcrease in the number of different elements. In most cases, the elements interact with each other in some( 73 )fashion: and the complexity of the wholencreases much more than linearly.
The complexity of software is a(an)( 74 )property, not an accidental one Hencedescriptions of a software entity that abstract away its complexity often abstract away its essence.Mathematics and the physical sciences made great strides for threecenturies by constructingsimplified models of complex phenomena, deriving properties fiom the models, and verifyingthose properties experimentally. This worked becausethe complexities( 75 ) in the modelswere not the .essential properties of the phenomena: It does not work when the complexities are the essence.
Many of the classical problems of developing software products derive from this essential complexi and its nonlinear uicreases with size. Not only .technical problems but management problems as well come from the coin plexity.
A. task
B.job
C.subroitune
D.Program
A.states
B.parts
C.conditions
D.Expressions
A.linear
B. nonlinear
C.Parallel
D.Addititive
A. surface
B. Outside
C.exterior
D.Essential
A. fixed
B. Included
C.ignored
D.stabilized
查看答案
試題參考答案:C、A、B、D、C
試題解析與討論:www.ichunya.com/exam/ExamDay.aspx?t1=4&day=2024/4/19
試題5
函數(shù)f和g的定義如下圖所示。執(zhí)行函數(shù)f時(shí)若采用引用(call by reference)方式調(diào)用函數(shù)g(a),則函數(shù)f的返回值為( )。查看答案
試題參考答案:D
試題解析與討論:www.ichunya.com/exam/ExamDay.aspx?t1=4&day=2024/4/19
試題6
使用 PERT 圖進(jìn)行進(jìn)度安排,不能清晰地描述 (1) ,但可以給出哪些任務(wù)完成后才能開始另一些任務(wù)。下面 PERT 圖所示工程從 A 到 K 的關(guān)鍵路徑是 (2) ,(圖中省略了任務(wù)的開始和結(jié)束時(shí)刻)。
(1)A、每個(gè)任務(wù)從何時(shí)開始
B、每個(gè)任務(wù)到何時(shí)結(jié)束
C、各任務(wù)之間的并行情況
D、各任務(wù)之間的依賴關(guān)系
(2)A、ABEGHIK
B、ABEGHJK
C、ACEGHIK
D、ACEGHJK
查看答案
試題參考答案:C、B
試題解析與討論:www.ichunya.com/exam/ExamDay.aspx?t1=4&day=2024/4/19
試題7
招聘系統(tǒng)要求求職的人年齡在20歲到60歲之間(含),學(xué)歷為本科、碩士或者博士,專業(yè)為計(jì)算機(jī)科學(xué)與技術(shù)、通信工程或者電子工程。其中( )不是好的測(cè)試用例。查看答案
試題參考答案:C
試題解析與討論:www.ichunya.com/exam/ExamDay.aspx?t1=4&day=2024/4/19
試題8
對(duì)于一個(gè)大型軟件來說,不加控制的變更很快就會(huì)引起混亂。為有效地實(shí)現(xiàn)變更控制,需借助于配置數(shù)據(jù)庫(kù)和基線的概念。 ( ) 不屬于配置數(shù)據(jù)庫(kù)。
A、開發(fā)庫(kù)
B、受控庫(kù)
C、信息庫(kù)
D、產(chǎn)品庫(kù)
查看答案
試題參考答案:C
試題解析與討論:www.ichunya.com/exam/ExamDay.aspx?t1=4&day=2024/4/19
試題9
運(yùn)行下面的 C 程序代碼段,會(huì)出現(xiàn)( )錯(cuò)誤。
int k=0;
for(;k<100;);
{k++;)
A.變量未定義
B.靜態(tài)語(yǔ)義
C.語(yǔ)法
D.動(dòng)態(tài)語(yǔ)義
查看答案
試題參考答案:D
試題解析與討論:www.ichunya.com/exam/ExamDay.aspx?t1=4&day=2024/4/19
試題10
給定教師關(guān)系Teacher(T_no,T_name,Dept_name,Tel),其中屬性T_no、T_name、Dept_name和Tel的含義分別為教師號(hào)、教師姓名、學(xué)院名和電話號(hào)碼。用SQL創(chuàng)建一個(gè)“給定學(xué)院名求該學(xué)院的教師數(shù)”的函數(shù)如下:查看答案
試題參考答案:A、D
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