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閱讀下列說(shuō)明和C++代碼,填補(bǔ)代碼中的空缺,將解答填入答題紙的對(duì)應(yīng)欄內(nèi)。
【說(shuō)明】
以下C++代碼實(shí)現(xiàn)一個(gè)簡(jiǎn)單客戶關(guān)系管理系統(tǒng)(CrM)中通過(guò)工廠(Customerfactory)對(duì)象來(lái)創(chuàng)建客戶(Customer)對(duì)象的功能。客戶分為創(chuàng)建成功的客戶(realCustomer)和空客戶(NullCustomer)??湛蛻魧?duì)象是當(dāng)不滿足特定條件時(shí)創(chuàng)建或獲取的對(duì)象。類間關(guān)系如圖6-1所示。

圖6-1
【C++代碼】
#include
#include
using namespace std;

class Customer{
protected:
string name;
public:
(   1   ) boll isNil()=0;
(   2   ) string getName()=0;
﹜;

class RealCustomer (   3   ){
Public:
realCustomer(string name){this->name=name;﹜
bool isNil(){ return false;  ﹜
string getName(){ return name;  ﹜
﹜;
class NullCustomer (    4   ) {
public:
bool isNil(){  return true; ﹜
string getName(){ return 〝Not Available in Customer Database〞; ﹜
﹜;

class Customerfactory{
public:
string names[3]={〝rob〞, 〝Joe〞,〝Julie〞﹜;
public:
Customer*getCustomer(string name){
for (int i=0;i<3;i++){
if (names[i].(   5   ) ){
return new realCustomer(name);


return (   6   );

﹜;

class CRM{
public:
void getCustomer(){
Customerfactory*(   7   );
Customer*customer1=cf->getCustomer(〝Rob〞);
Customer*customer2=cf->getCustomer(〝Bob〞);
Customer*customer3=cf->getCustomer(〝Julie〞);
Customer*customer4=cf->getCustomer(〝Laura〞);

cout<<〝Customers〞<cout cout cout cout delete cf;

﹜;
int main(){
CRM*crs=new CRM();
crs->getCustomer();
delete crs;
return 0;


/*程序輸出為:
Customers
rob
Not Available in Customer Database
Julie
Not Available in Customer Database
*/

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